49x^2+8x=15x

Solution for 49x^2+8x=15x equation:

49x^2+8x=15x

We move all terms to the left:

49x^2+8x-(15x)=0

We add all the numbers together, and all the variables

49x^2-7x=0

a = 49; b = -7; c = 0;
Δ = b2-4ac
Δ = -72-4·49·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-7}{2*49}=\frac{0}{98}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+7}{2*49}=\frac{14}{98}
=1/7
$